Voltage Divider Circuit: Formula & Design
Voltage divider formula (Vout = Vin × R2/(R1+R2)), load effect analysis, and design examples. Avoid common measurement errors.
Voltage Divider Formula & Calculator: Vout = Vin × R2/(R1+R2) (2026)
Quick formula: Vout = Vin × R2 / (R1 + R2). With a load: R2_eff = R2 ‖ R_load, then apply same formula. Rule of thumb: keep load resistance ≥10× R2 for less than ~5% sag. Use the Voltage Divider Calculator for rapid design.
A resistive voltage divider uses two resistors, R1 (upper) and R2 (lower), in series between an input voltage Vin and ground. The output node between R1 and R2 provides a scaled voltage Vout given, in the ideal unloaded case, by the standard relationship:
- Vout = Vin × R2 / (R1 + R2)
Voltage dividers are one of the most common building blocks in analog and mixed-signal circuits. They are used to:
- Scale a supply or sensor voltage down to an ADC input range
- Generate reference voltages for comparators or amplifiers
- Bias transistor or op-amp stages
- Sense high voltages through a resistive ratio (often together with series resistor networks or broader series circuit analysis)
This guide focuses on practical voltage divider design, including:
- The ideal two-resistor divider formula and its assumptions
- How load resistance changes the effective ratio
- Error sources: tolerance, temperature drift, and power dissipation
- A design workflow using the Voltage Divider Calculator
If you mainly care about numerical results and a practical sequence of steps, you can jump directly to Design workflow with the Voltage Divider Calculator and Worked design examples; the earlier sections explain the assumptions and error mechanisms behind those results.
Concept and ideal voltage divider formula
A basic resistive divider uses two resistors, R1 and R2, in series between an input voltage Vin and ground.
- R1 is the upper resistor (connected to Vin)
- R2 is the lower resistor (connected to ground)
The output voltage Vout is taken from the junction between R1 and R2.
Ideal two-resistor formula (no load)
In the ideal unloaded case:
-
Series current: I_div = Vin / (R1 + R2)
-
Output voltage:
Vout = Vin × (R2 / (R1 + R2))
Key observations:
- Ratio-based: Vout / Vin = R2 / (R1 + R2)
- Only the ratio of R1 and R2 matters, not their absolute scale
- If R1 = R2 → Vout = 0.5 × Vin
For quick checks and calculator verification, keep this ideal formula in mind.
Choosing absolute resistor values
Even though the ratio sets Vout, the absolute values of R1 and R2 matter for:
- Divider current: I_div = Vin / (R1 + R2)
- Power dissipation in R1 and R2
- Sensitivity to load (see Load effects: why real dividers sag below)
Rule of thumb:
- Higher total resistance → lower current, lower power, more sensitive to load
- Lower total resistance → higher current, higher power, more robust to load, but more heat
- Very high-value dividers (multi-megaohm range) are more sensitive to PCB leakage, input bias currents, and noise, which can dominate small-signal measurement errors.
The Voltage Divider Calculator's design_divider mode targets a reasonable default current (e.g., around 1 mA) and then chooses resistor values accordingly. For more complex resistor networks or when you need to realise non-standard ratios with available parts, the Resistance Calculator can help you analyse series/parallel combinations and equivalent resistance.
Load effects: why real dividers sag
In most real circuits, the divider output drives a load with finite resistance R_load.
- The load is connected between Vout and ground
- R2 and R_load are effectively in parallel
The effective lower resistance becomes:
- R2_eff = R2 ‖ R_load = (R2 × R_load) / (R2 + R_load)
The actual output voltage is then:
- Vout_actual = Vin × (R2_eff / (R1 + R2_eff))
Example – equal-value divider driving a finite load
A 10 kΩ / 10 kΩ divider from 10 V ideally produces 5 V.
- Vin = 10 V
- R1 = 10 kΩ
- R2 = 10 kΩ
- Ideal Vout = 10 × (10k / (10k + 10k)) = 5 V
Now connect a 10 kΩ load from Vout to ground.
-
Compute effective lower resistance:
- R2_eff = 10k ‖ 10k = (10k × 10k) / (10k + 10k) = 5 kΩ
-
Compute actual Vout:
- Vout_actual = 10 × (5k / (10k + 5k)) = 10 × (5/15) ≈ 3.33 V
The output drops from 5 V (ideal) to about 3.3 V due to load—a 33% error.
Rule-of-thumb for load impedance
To keep load error small:
- Make the divider's output impedance much smaller than the load
- A common starting point is:
- Design so that, at the intended operating point, the divider current is at least an order of magnitude larger than the worst-case load current (I_div ≳ 10 × I_load). The exact relationship between this current ratio and voltage error depends on the target Vout/Vin ratio.
- For mid-scale dividers with R1 ≈ R2, choosing R_load ≫ R2 gives smaller error; example values are summarised below.
For a simple mid-scale divider with R1 = R2 and no additional loading, the ideal ratio is Vout/Vin = 0.5. When a finite load R_load is connected from Vout to ground, the effective lower resistance becomes R2‖R_load and the actual Vout/Vin is reduced. The table below shows typical values for several load ratios k = R_load/R2 using the exact relationship Vout/Vin = k/(1 + 2k):
| Load ratio k = R_load/R2 | Vout/Vin | Approximate error vs ideal 0.5 |
|---|---|---|
| ∞ (no load) | 0.500 | 0% |
| 100 | ≈0.498 | ≈−0.5% |
| 10 | ≈0.476 | ≈−4.8% |
| 5 | ≈0.455 | ≈−9.1% |
| 1 | 0.333 | −33% |
This illustrates that the widely used “10× rule” still allows several percent sag for a mid-scale divider; for ≲1% error in that case, the load resistance should be on the order of one to two orders of magnitude larger than the lower divider resistor, or the node should be buffered.
If you cannot meet this without excessive power, consider:
- Buffering Vout with an op-amp
- Using a dedicated reference IC or regulator instead of a pure resistive divider
Error sources beyond load: tolerance, temperature, and drift
Even if the load is high-impedance, other factors introduce errors.
Resistor tolerance
Real resistors have tolerance (e.g., ±1%, ±5%). For a two-resistor divider:
- Worst-case Vout error can be approximated by combining the tolerances of R1 and R2
- If both are 5% parts, the ratio error can approach ±10% in the worst case
Mitigations:
- Use 1% metal film or better for sensor and reference work
- Use matched resistor networks for tight tracking
- For quantitative drift and ratio-change estimates across ambient range, use datasheet temperature-coefficient values together with the Temperature Coefficient Calculator, which implements the standard linear temperature-coefficient model commonly used in resistor datasheets.
Temperature coefficient
Resistance changes with temperature, typically quoted as ppm/°C or %/°C.
- General-purpose carbon film: larger drift
- Metal film and thin film: lower drift, better tracking
For many practical circuits, ratio change over temperature is the key concern, not absolute resistance.
Power dissipation, efficiency, and operating cost
Divider resistors dissipate power:
- P_R1 = I_div² × R1
- P_R2 = I_div² × R2
- P_total ≈ Vin² / (R1 + R2)
If power is high relative to resistor rating, self-heating can change resistance and long-term stability.
Guidelines:
- Run resistors well below their rated power (e.g., ≤ 50% of rating for continuous operation)
- Account for ambient temperature and enclosure conditions
For dividers that are energised for long periods (for example, across a DC bus or mains-derived DC rail), even a few hundred milliwatts of continuous dissipation can become a non-trivial energy cost. Approximate annual energy is P_total × operating hours; combine this with your local electricity tariff (tariff-dependent) or use the Power Calculator together with the Energy Calculator to estimate impact on system efficiency. Where the divider is fed through appreciable wiring length or a distribution feeder, use the Voltage Drop Calculator to assess additional conductor losses and voltage sag outside the divider itself.
Design workflow with the Voltage Divider Calculator
A practical workflow for designing a divider is:
-
Define the function
- Level shifting (e.g., 5 V → 3.3 V logic)
- Reference generation (e.g., 10 V → 2.5 V ref)
- Sensing a higher voltage (e.g., 48 V bus to 3.3 V ADC)
-
Specify Vin, desired Vout, and load characteristics
- Nominal Vin range
- Target Vout and acceptable error range
- Load resistance or current (ADC input impedance, amplifier input bias, etc.)
-
Choose a target divider current
- Light loads: 0.1–1 mA often sufficient
- Heavier or noisier environments may need more current
-
Use the Voltage Divider Calculator
design_dividermode: specify Vin and Vout; choose resistor series (E12/E24/E48)- Review suggested R1 and R2, divider current, and power
-
Check load-induced error
- If the calculator supports load current or R_load, include it
- Otherwise, compute R2_eff and Vout_actual manually using formulas from Load effects: why real dividers sag
-
Iterate on resistor values and series
- Tighten tolerance or lower total resistance if accuracy is insufficient
- Increase total resistance if power dissipation or current draw is too high
Worked design examples
5 V to 3.3 V logic level interface
Goal: Scale 5 V logic to ~3.3 V for a microcontroller input with high impedance.
-
Requirements
- Vin = 5 V
- Target Vout ≈ 3.3 V
- Load: microcontroller input, effectively high impedance (no significant DC current)
-
Ideal ratio
- Vout / Vin = R2 / (R1 + R2) = 3.3 / 5 = 0.66
- Choose convenient R2 = 10 kΩ
- Solve for R1:
- 3.3 = 5 × 10k / (R1 + 10k)
- (R1 + 10k) = 5 × 10k / 3.3 ≈ 15.15 kΩ
- R1 ≈ 5.15 kΩ → use 5.1 kΩ (E24 series)
-
Check results
- Vout ≈ 5 × (10k / (5.1k + 10k)) ≈ 3.30 V
- Divider current ≈ 5 / 15.1k ≈ 0.331 mA
- Power in R1 ≈ (0.331 mA)² × 5.1k ≈ 0.56 mW (well below common 0.125 W or 0.25 W ratings)
This design is adequate for most logic-level interfaces.
48 V bus sense for 3.3 V ADC input
Goal: Sense a 48 V DC bus with a microcontroller ADC that has a 3.3 V full-scale range.
-
Requirements
- Vin_max = 60 V (include margin for overvoltage)
- Vout_max ≈ 3.3 V at Vin = 60 V
- ADC input resistance: ~1 MΩ (high-impedance), sample-and-hold behaviour
-
Ideal ratio at Vin = 60 V
- Vout / Vin ≈ 3.3 / 60 = 0.055
- Choose R2 = 10 kΩ
- R1 ≈ (1/ratio − 1) × R2 ≈ (1/0.055 − 1) × 10k ≈ (18.18 − 1) × 10k ≈ 171.8 kΩ
- Use R1 ≈ 174 kΩ or 180 kΩ from preferred series
-
Check divider current at 60 V
- With R1 = 180 kΩ, R2 = 10 kΩ → R_total ≈ 190 kΩ
- I_div ≈ 60 / 190k ≈ 0.316 mA
- P_total ≈ 60 × 0.316 mA ≈ 18.9 mW (acceptable)
-
Consider ADC sampling
- During sampling, the ADC briefly draws current into its sample capacitor
- 10 kΩ output impedance is usually acceptable but check your ADC datasheet
- If acquisition time is short or source impedance limits are strict, lower R1 and R2 proportionally
-
Safety considerations
- 48–60 V DC buses are close to the upper boundary used for SELV and related limited-voltage categories in many IEC/UL standards; see Safety, standards, and voltage limits below before using simple resistive dividers on these systems.
Safety, standards, and voltage limits
Resistive voltage dividers do not provide galvanic isolation and should not be relied on alone for protection against electric shock or for meeting reinforced insulation requirements.
- Many IEC/UL product- and measurement-safety standards define limits for SELV or ES1 circuits in terms of accessible voltage, typically on the order of 30 V_rms (≈42.4 V peak) for AC and about 60 V DC for equipment safety, while installation standards such as IEC 60364 often define extra-low-voltage circuits as not exceeding about 50 V AC or 120 V ripple-free DC. The applicable limit, and the associated creepage/clearance requirements, must always be taken from the specific standard and environment that govern the equipment and installation.
- For dividers connected to 48–60 V DC buses or higher, check:
- Individual resistor voltage rating and surge capability
- Series-string voltage distribution if multiple resistors share the drop
- Creepage/clearance on the PCB, contamination degree, and insulation coordination
- For mains-referenced or grid-connected measurements, prefer approaches that use properly rated isolation devices (for example, isolated amplifiers, potential transformers, or certified measurement modules) and follow the applicable IEC/UL and local wiring-code requirements.
Wheatstone Bridge: Precision Measurement Dividers
A Wheatstone bridge is two voltage dividers placed in parallel across the same supply voltage, with the output taken as the differential voltage between the two midpoints. It is the foundational circuit for precision resistance sensing in strain gauges, RTDs (Pt100/Pt1000), thermistors, and load cells.
Bridge Topology and Balance Condition
The four-arm bridge has:
- Left divider: R1 (upper) and R2 (lower); midpoint voltage = Vin × R2/(R1+R2)
- Right divider: R3 (upper) and R4 (lower); midpoint voltage = Vin × R4/(R3+R4)
The differential output voltage:
Vout = Vin × [R2/(R1+R2) − R4/(R3+R4)]
Balanced condition (Vout = 0):
R1/R2 = R3/R4, equivalently R1 × R4 = R2 × R3
In the null-detector measurement method, a calibrated variable resistor replaces one arm and is adjusted until Vout = 0. The unknown resistance is then: R_x = R_var × (R1/R2). This approach is immune to supply voltage variation, giving extremely high accuracy from purely resistor-ratio relationships.
Bridge Sensitivity for Small Resistance Changes
When one arm changes by ΔR (all four arms nominally equal at R):
ΔVout ≈ (Vin / 4) × (ΔR / R) — valid for ΔR ≪ R
Worked example — 350 Ω foil strain gauge, single active arm:
- Vin = 5V excitation, all arms = 350 Ω at balance
- Gauge factor GF = 2.0 (typical for metallic foil gauges)
- Applied strain ε = 1,000 µε (microstrain) = 1×10⁻³
- ΔR/R = GF × ε = 2.0 × 1×10⁻³ = 0.002
- ΔVout = (5 / 4) × 0.002 = 2.5 mV
This 2.5 mV differential signal requires a high-gain, low-offset instrumentation amplifier (INA). A full-bridge configuration (four active gauges — two in tension, two in compression) quadruples the output to 10 mV and cancels temperature drift, making it the preferred approach for precision load cells.
Common Wheatstone Bridge Applications
| Application | Active Arms | Sensor | Typical ΔR/R | Output Sensitivity |
|---|---|---|---|---|
| Strain gauge (single arm) | 1 of 4 | Foil gauge, GF=2 | 0.001–0.01 (1–5 kµε) | ~1.25 mV/V full-scale |
| Strain gauge (full bridge) | 4 of 4 | 4 gauges (push-pull) | 0.001–0.01 | ~5 mV/V full-scale |
| RTD temperature (Pt100) | 1 of 4 | Pt100 (α=0.00385/°C) | 0.00385/°C | ~1 mV/V/°C (near balance) |
| NTC thermistor (10 kΩ) | 1 of 4 | 10kΩ at 25°C, B=3950K | −0.04/°C near 25°C | ~10 mV/V/°C (highly nonlinear) |
| Unknown resistance | 1 variable | R_var adjusted to null | — | Null: R_x = R_var×(R1/R2) |
Note: For RTD measurements, a 3-wire or 4-wire connection is preferred over a simple 2-wire bridge arm to cancel lead resistance errors. In high-precision applications (e.g., NIST-traceable calibration), the Kelvin double bridge is used for resistances below about 1 Ω.
Standard Resistor E-Series for Precision Divider Design
When designing voltage dividers and Wheatstone bridges, resistor values must come from standard E-series preferred numbers. The series number indicates values per decade:
E12 series (12 values/decade, nominally ±10% tolerance): 1.0, 1.2, 1.5, 1.8, 2.2, 2.7, 3.3, 3.9, 4.7, 5.6, 6.8, 8.2 (×10ⁿ)
E24 series (24 values/decade, nominally ±5% tolerance): 1.0, 1.1, 1.3, 1.5, 1.6, 1.8, 2.0, 2.2, 2.4, 2.7, 3.0, 3.3, 3.6, 3.9, 4.3, 4.7, 5.1, 5.6, 6.2, 6.8, 7.5, 8.2, 9.1 (×10ⁿ)
E48 and E96 series are used for precision 1% and 0.1% applications.
Common voltage division ratios achievable with E24 pairs (copper, 10 kΩ range):
| Target Vout/Vin | Supply → Output | R1 (upper) | R2 (lower) | Actual Ratio | Error |
|---|---|---|---|---|---|
| 0.500 | 10V → 5.0V | 10 kΩ | 10 kΩ | 0.5000 | 0.0% |
| 0.660 | 5V → 3.3V | 5.1 kΩ | 10 kΩ | 0.6623 | +0.3% |
| 0.330 | 10V → 3.3V | 20 kΩ | 10 kΩ | 0.3333 | +1.0% |
| 0.250 | 12V → 3.0V | 30 kΩ | 10 kΩ | 0.2500 | 0.0% |
| 0.183 | 3.3V → 0.6V | 22 kΩ | 5.1 kΩ | 0.1882 | +2.8% |
| 0.055 | 60V → 3.3V | 180 kΩ | 10 kΩ | 0.0526 | −4.4% |
| 0.033 | 100V → 3.3V | 300 kΩ | 10 kΩ | 0.0323 | −2.1% |
For ratios with >2% error, combine two E24 resistors in series for R1 or R2 to achieve a closer sum (e.g., 180k+12k = 192kΩ gives 10k/(192k+10k) = 4.95% → 5V from 100V). Use the Voltage Divider Calculator in E-series mode to automate this search.
When to use dividers vs regulators or buffers
Resistive dividers are not a replacement for proper regulators or buffer circuits when:
- Load current is significant or varies over a wide range
- You need tight line/load regulation
- Efficiency is important (dividers continuously burn power)
Use voltage dividers for:
- High-impedance sense points and references
- Biasing and level shifting with small currents
- Educational examples and quick experiments
Use regulators or buffered references for:
- Supplying power to active circuits
- Precision references that must hold under varying load
Summary and next steps
Key points:
- The ideal divider follows Vout = Vin × R2 / (R1 + R2).
- Load resistance in parallel with R2 reduces effective resistance and pulls Vout down.
- Tolerance, temperature drift, and power dissipation further contribute to error.
- Good design balances accuracy, current draw, and component cost.
- The Voltage Divider Calculator automates ratio and resistor selection while exposing key parameters like current and power.
To go further:
- Try the calculator with different Vin, Vout, and series options
- Review Series and Parallel Circuits for underlying theory
- Combine with the Ohm's Law calculator for quick current and power checks
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Frequently Asked Questions
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